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Chapter 01
Introduction
Multiple Choice Questions
1. Physics is relevant to which of the following
fields?
A. Chemistry
B. Biology
C. Medicine
D. Architecture
E. all of these choices are correct
A. Chemistry
B. Biology
C. Medicine
D. Architecture
E. all of these choices are correct
Section: 1.1 Why Study Physics?
2. In everyday language, speed and velocity are
synonyms, but in physics
A. velocity has only magnitude.
B. speed has only direction.
C. velocity has magnitude and direction.
D. speed has magnitude and direction.
E. velocity has only direction.
A. velocity has only magnitude.
B. speed has only direction.
C. velocity has magnitude and direction.
D. speed has magnitude and direction.
E. velocity has only direction.
Section: 1.2 Talking Physics
3. In everyday language, power and force are similar,
but in physics
A. force has only magnitude.
B. power has only direction.
C. force has magnitude and direction.
D. power has magnitude and direction.
E. none of these choices are correct
A. force has only magnitude.
B. power has only direction.
C. force has magnitude and direction.
D. power has magnitude and direction.
E. none of these choices are correct
Section: 1.2 Talking Physics
4. Algebraic symbols in physics equations represent
physical quantities; therefore
A. the symbols represent numbers only.
B. the symbols represent numbers and units.
C. the symbols consist of units only.
D. the symbols are only abstract.
E. the symbols are only imaginary.
A. the symbols represent numbers only.
B. the symbols represent numbers and units.
C. the symbols consist of units only.
D. the symbols are only abstract.
E. the symbols are only imaginary.
Section: 1.2 Talking Physics
5. The last page of a book is numbered 814 and the
book is 3.00 cm thick. What is the average thickness of each page?
A. 2.54 ´ 103 cm
B. 2.54 ´ 10-3 cm
C. 7.37 ´ 10-3 cm
D. 3.92 ´ 10-3 cm
A. 2.54 ´ 103 cm
B. 2.54 ´ 10-3 cm
C. 7.37 ´ 10-3 cm
D. 3.92 ´ 10-3 cm
Section: 1.3 The Use of Mathematics
6. The diameter of a circle is doubled. By what factor
is the area changed?
A. Ö2
B. 2
C. 4
D. Ö4
E. 1
A. Ö2
B. 2
C. 4
D. Ö4
E. 1
Section: 1.3 The Use of Mathematics
7. The radius of a circle is increased by 5%. The
percentage increase of the circumference is
A. 5%.
B. 10%.
C. 12%.
D. 16%.
A. 5%.
B. 10%.
C. 12%.
D. 16%.
Section: 1.3 The Use of Mathematics
8. The radius of a circle is increased by 5%. The
percentage increase of the area is
A. 5%.
B. 10%.
C. 12%.
D. 16%.
A. 5%.
B. 10%.
C. 12%.
D. 16%.
Section: 1.3 The Use of Mathematics
9. The radius of a circle is tripled. By what factor
is the area changed?
A. 3
B. 6
C. 9
D. 12
A. 3
B. 6
C. 9
D. 12
Section: 1.3 The Use of Mathematics
10. The area of a circle is found to be half of its
original value after the radius is multiplied by a certain factor. What is the
factor?
A. 1/4
B. 1/2
C. Ö2
D. 1/Ö2
A. 1/4
B. 1/2
C. Ö2
D. 1/Ö2
Section: 1.3 The Use of Mathematics
11. What is the percentage increase in size when
ordering a 14-inch rather than a 12-inch pizza?
A. 16%
B. 26%
C. 36%
D. 46%
A. 16%
B. 26%
C. 36%
D. 46%
Section: 1.3 The Use of Mathematics
12. By what factor larger is a 12-inch pizza than a
10-inch pizza?
A. 1.2
B. 1.1
C. 1.4
D. 1.6
A. 1.2
B. 1.1
C. 1.4
D. 1.6
Section: 1.3 The Use of Mathematics
13. If the surface area of a sphere is increased by a
factor of 3, by what factor does the radius of the sphere change?
A. 1.14
B. 1.73
C. 2.00
D. 2.24
A. 1.14
B. 1.73
C. 2.00
D. 2.24
Section: 1.3 The Use of Mathematics
14. If the surface area of a sphere is increased by
16%, by what percentage has the radius been changed?
A. 16%
B. 8.1%
C. 7.7%
D. 12%
A. 16%
B. 8.1%
C. 7.7%
D. 12%
Section: 1.3 The Use of Mathematics
15. The volume of a sphere is 8.00 m3. The
radius of the sphere is
A. 1.24 m.
B. 2.00 m.
C. 2.65 m.
D. 3.00 m.
A. 1.24 m.
B. 2.00 m.
C. 2.65 m.
D. 3.00 m.
Section: 1.3 The Use of Mathematics
16. The radius of a sphere is 2.00 m. The surface area
of the sphere is
A. 36.7 m2.
B. 50.3 m2.
C. 72.5 m2.
D. 75.0 m2.
A. 36.7 m2.
B. 50.3 m2.
C. 72.5 m2.
D. 75.0 m2.
Section: 1.3 The Use of Mathematics
17. By what factor does the volume of a cube increase
if the length of the edges are doubled?
A. 2
B. 4
C. 6
D. 8
A. 2
B. 4
C. 6
D. 8
Section: 1.3 The Use of Mathematics
18. By what factor does the volume of a cube increase
if the length of the edges are tripled?
A. 6
B. 9
C. 3
D. 27
A. 6
B. 9
C. 3
D. 27
Section: 1.3 The Use of Mathematics
19. The side of a cube is decreased by 6%. The
percentage decrease of the volume of the cube is
A. 6%.
B. 9%.
C. 12%.
D. 17%.
A. 6%.
B. 9%.
C. 12%.
D. 17%.
Section: 1.3 The Use of Mathematics
20. If the length of a box is reduced by one-third and
the width and height are doubled, by what factor has the volume changed?
A. 4/3
B. 2/3
C. 3/4
D. 3/2
A. 4/3
B. 2/3
C. 3/4
D. 3/2
Section: 1.3 The Use of Mathematics
21. The side of a cube is increased by 5%. The
percentage increase of the surface area of the cube is
A. 5%.
B. 10%.
C. 12%.
D. 16%.
E. 18%.
A. 5%.
B. 10%.
C. 12%.
D. 16%.
E. 18%.
Section: 1.3 The Use of Mathematics
22. The price of gasoline goes up 6% on Monday night
and then goes down 7% today. What is the net percentage change in the price of
gasoline from Monday?
A. 1.0%
B. 2.0%
C. 1.4%
D. -1.0%
A. 1.0%
B. 2.0%
C. 1.4%
D. -1.0%
Section: 1.3 The Use of Mathematics
23. 1.0 kilometer equals ___________ nanometers.
A. 1.0 ´ 10+12
B. 1.0 ´ 10+6
C. 1.0 ´ 10+4
D. 1.0 ´ 10-3
A. 1.0 ´ 10+12
B. 1.0 ´ 10+6
C. 1.0 ´ 10+4
D. 1.0 ´ 10-3
Section: 1.4 Scientific Notation and Significant Figures
24. 1.0 centimeter equals ___________
micrometers.
A. 1.0 ´ 10+12
B. 1.0 ´ 10+6
C. 1.0 ´ 10+4
D. 1.0 ´ 10-3
A. 1.0 ´ 10+12
B. 1.0 ´ 10+6
C. 1.0 ´ 10+4
D. 1.0 ´ 10-3
Section: 1.4 Scientific Notation and Significant Figures
25. 1.0 micrometer equals _____________
millimeters.
A. 1.0 ´ 10-6
B. 1.0 ´ 10-3
C. 1.0 ´ 10+3
D. 1.0 ´ 10+6
A. 1.0 ´ 10-6
B. 1.0 ´ 10-3
C. 1.0 ´ 10+3
D. 1.0 ´ 10+6
Section: 1.4 Scientific Notation and Significant Figures
26. The number of significant figures in 3.24 cm
is
A. 2.
B. 3.
C. 4.
D. 5.
A. 2.
B. 3.
C. 4.
D. 5.
Section: 1.4 Scientific Notation and Significant Figures
27. The precision and number of significant figures in
1.003 km is
A. precision = .0001 km, significant figure = 4.
B. precision = .001 km, significant figure = 4.
C. precision = .0001 km, significant figure = 3.
D. precision = .001 km, significant figure = 3.
E. precision = .0001 km, significant figure = 2.
A. precision = .0001 km, significant figure = 4.
B. precision = .001 km, significant figure = 4.
C. precision = .0001 km, significant figure = 3.
D. precision = .001 km, significant figure = 3.
E. precision = .0001 km, significant figure = 2.
Section: 1.4 Scientific Notation and Significant Figures
28. The precision and number of significant figures in
0.0045 mm is
A. precision = .0001 mm, significant figures = 4.
B. precision = .001 mm, significant figures = 4.
C. precision = .0001 mm, significant figures = 3.
D. precision = .001 mm, significant figures = 3.
E. precision = .0001 mm, significant figures = 2.
A. precision = .0001 mm, significant figures = 4.
B. precision = .001 mm, significant figures = 4.
C. precision = .0001 mm, significant figures = 3.
D. precision = .001 mm, significant figures = 3.
E. precision = .0001 mm, significant figures = 2.
Section: 1.4 Scientific Notation and Significant Figures
29. The length 4.221 cm is added to 0.01 cm. The
appropriately rounded sum is
A. 4.22 cm.
B. 4.2301 cm.
C. 4.23 cm.
D. 4.2 cm.
E. 4.21 cm.
A. 4.22 cm.
B. 4.2301 cm.
C. 4.23 cm.
D. 4.2 cm.
E. 4.21 cm.
Section: 1.4 Scientific Notation and Significant Figures
30. The length 3.76 mm is multiplied by 0.05 mm. The
appropriately rounded product is
A. 0.18 mm2.
B. 0.2 mm2.
C. 0.19 mm2.
D. 0.1881 mm2.
E. 0.29 mm2.
A. 0.18 mm2.
B. 0.2 mm2.
C. 0.19 mm2.
D. 0.1881 mm2.
E. 0.29 mm2.
Section: 1.4 Scientific Notation and Significant Figures
31. The length 3.76 mm is multiplied by 0.0232 mm. The
appropriately rounded product is
A. 0.082 mm2.
B. 0.09 mm2.
C. 0.087 mm2.
D. 0.0872 mm2.
E. 0.08723 mm2.
A. 0.082 mm2.
B. 0.09 mm2.
C. 0.087 mm2.
D. 0.0872 mm2.
E. 0.08723 mm2.
Section: 1.4 Scientific Notation and Significant Figures
32. The length 3.76 mm is divided by 6 mm. The
appropriately rounded ratio is
A. 0.627.
B. 0.63.
C. 0.6.
D. 0.62666.
E. 0.6267.
A. 0.627.
B. 0.63.
C. 0.6.
D. 0.62666.
E. 0.6267.
Section: 1.4 Scientific Notation and Significant Figures
33. The length 3.76 mm is divided by 0.0232 mm. The
rounded ratio is
A. 160.
B. 162.
C. 162.1.
D. 162.07.
E. 162.069.
A. 160.
B. 162.
C. 162.1.
D. 162.07.
E. 162.069.
Section: 1.4 Scientific Notation and Significant Figures
34. A cube is 1.0 inch in length on the side (1 in. =
2.540 cm). The volume of the cube is
A. 1.64 ´ 10+1 cm3.
B. 1.6387 ´ 10+1 cm3.
C. 1.6 ´ 10+1 cm3.
D. 1.639 ´ 10+1 cm3.
A. 1.64 ´ 10+1 cm3.
B. 1.6387 ´ 10+1 cm3.
C. 1.6 ´ 10+1 cm3.
D. 1.639 ´ 10+1 cm3.
Section: 1.4 Scientific Notation and Significant Figures
35. The number of seconds in a 30-day month is
A. 2.59 ´ 10+6.
B. 2.592 ´ 10+6.
C. 2.5920 ´ 10+6.
D. 2.592000 ´ 10+6.
A. 2.59 ´ 10+6.
B. 2.592 ´ 10+6.
C. 2.5920 ´ 10+6.
D. 2.592000 ´ 10+6.
Section: 1.4 Scientific Notation and Significant Figures
36. The population of the United States is
approximately 290,000,000. Write this in scientific notation.
A. 2.9 ´ 107
B. 290 ´ 107
C. 2.90 ´ 107
D. 2.9 ´ 108
A. 2.9 ´ 107
B. 290 ´ 107
C. 2.90 ´ 107
D. 2.9 ´ 108
Section: 1.4 Scientific Notation and Significant Figures
37. Using the following unit conversions: 1.00 fluid
ounce = 29.573 ml, 1.00 L = 1000 cm3, density of water = 1.00 gm/cm3,
the number of fluid ounces in a kg of water is
A. 48.8 fluid ounces.
B. 40.1 fluid ounces.
C. 33.8 fluid ounces.
D. 25.7 fluid ounces.
A. 48.8 fluid ounces.
B. 40.1 fluid ounces.
C. 33.8 fluid ounces.
D. 25.7 fluid ounces.
Section: 1.5 Units
38. If the radius of the Earth is 6400.0 km, and the
atmosphere is 10.0 km high, then the volume of air around the Earth is
A. 5.135 ´ 10+18 m3.
B. 3.605 ´ 10+16 m3.
C. 5.14 ´ 10+18 m3.
D. 6.211 ´ 10+12 m3.
A. 5.135 ´ 10+18 m3.
B. 3.605 ´ 10+16 m3.
C. 5.14 ´ 10+18 m3.
D. 6.211 ´ 10+12 m3.
Section: 1.5 Units
39. How many square centimeters are there in 1 square
foot (1 in. = 2.540 cm)?
A. 9.290 ´ 103 cm2
B. 929.0 cm2
C. 9.290 ´ 104 cm2
D. 92.90 cm2
E. 9.3 ´ 102 cm2
A. 9.290 ´ 103 cm2
B. 929.0 cm2
C. 9.290 ´ 104 cm2
D. 92.90 cm2
E. 9.3 ´ 102 cm2
Section: 1.5 Units
40. One angstrom = 10-10 m and one fermi =
10-15 m. What is the relationship between these units?
A. 1 angstrom = 105 fermi
B. 1 angstrom = 10-5 fermi
C. 1 angstrom = 10-25 fermi
D. 1 angstrom = 1025 fermi
A. 1 angstrom = 105 fermi
B. 1 angstrom = 10-5 fermi
C. 1 angstrom = 10-25 fermi
D. 1 angstrom = 1025 fermi
Section: 1.5 Units
41. Which of the SI prefixes is used to indicate 109?
A. kilo
B. mega
C. giga
D. tera
E. nano
A. kilo
B. mega
C. giga
D. tera
E. nano
Section: 1.5 Units
42. Which of the following is not a SI base
unit?
A. kelvin
B. kilogram
C. newton
D. second
E. meter
A. kelvin
B. kilogram
C. newton
D. second
E. meter
Section: 1.5 Units
43. To be dimensionally consistent, distance [L],
velocity [L/T], and time [T] must be related as
A. distance = time/velocity.
B. distance = velocity/time.
C. distance = time/velocity2.
D. distance = velocity ´ time2.
E. distance = velocity ´ time.
A. distance = time/velocity.
B. distance = velocity/time.
C. distance = time/velocity2.
D. distance = velocity ´ time2.
E. distance = velocity ´ time.
Section: 1.6 Dimensional Analysis
44. To be dimensionally consistent, distance [L],
velocity [L/T], and acceleration [L/T2] must be related as
A. distance = velocity2/acceleration.
B. distance = velocity /acceleration.
C. distance = velocity2 ´ acceleration.
D. distance = velocity ´ acceleration2.
E. distance = velocity2/acceleration.
A. distance = velocity2/acceleration.
B. distance = velocity /acceleration.
C. distance = velocity2 ´ acceleration.
D. distance = velocity ´ acceleration2.
E. distance = velocity2/acceleration.
Section: 1.6 Dimensional Analysis
45. To be dimensionally consistent, the formula
velocity = frequency ´ wavelength must be related as follows where
velocity [L/T], frequency [1/T], and wavelength [L]
A. velocity = frequency2 ´ wavelength.
B. velocity = frequency ´ wavelength.
C. velocity = frequency/wavelength.
D. velocity = frequency/wavelength2.
A. velocity = frequency2 ´ wavelength.
B. velocity = frequency ´ wavelength.
C. velocity = frequency/wavelength.
D. velocity = frequency/wavelength2.
Section: 1.6 Dimensional Analysis
46. To be dimensionally consistent, velocity [L/T],
pressure [M/LT2], and density [M/L2] must be related
as
A. velocity = pressure/density.
B. velocity2 = pressure/density2.
C. velocity = pressure/density2.
D. velocity2 = pressure/density.
A. velocity = pressure/density.
B. velocity2 = pressure/density2.
C. velocity = pressure/density2.
D. velocity2 = pressure/density.
Section: 1.6 Dimensional Analysis
47. To be dimensionally consistent, velocity [L/T],
force [ML/T2], mass [M], and length [L] must be related as
A. velocity2 = force length/mass.
B. velocity2 = force length/mass2.
C. velocity = force length2/mass.
D. velocity = force length/mass.
A. velocity2 = force length/mass.
B. velocity2 = force length/mass2.
C. velocity = force length2/mass.
D. velocity = force length/mass.
Section: 1.6 Dimensional Analysis
48. To be dimensionally consistent, pressure [M/LT2],
density [M/L3], and velocity [L/T] must be related as
A. pressure2 = density ´ velocity2.
B. pressure = density ´ velocity2.
C. pressure = density ´ velocity.
D. pressure = density2 ´ velocity.
A. pressure2 = density ´ velocity2.
B. pressure = density ´ velocity2.
C. pressure = density ´ velocity.
D. pressure = density2 ´ velocity.
Section: 1.6 Dimensional Analysis
49. To be dimensionally consistent, force [ML/T2],
pressure [M/LT2], and length [L] must be related as
A. force = pressure2 ´ length2.
B. force = pressure2 ´ length.
C. force = pressure ´ length2.
D. force = pressure ´ length.
A. force = pressure2 ´ length2.
B. force = pressure2 ´ length.
C. force = pressure ´ length2.
D. force = pressure ´ length.
Section: 1.6 Dimensional Analysis
50. To be dimensionally consistent, distance [L],
acceleration [L/T2], and time [T] must be related as
A. distance = acceleration2 ´ time2.
B. distance = acceleration ´ time.
C. distance = acceleration ´ time2.
D. distance = acceleration2 ´ time.
A. distance = acceleration2 ´ time2.
B. distance = acceleration ´ time.
C. distance = acceleration ´ time2.
D. distance = acceleration2 ´ time.
Section: 1.6 Dimensional Analysis
51. To be dimensionally consistent, velocity [L/T],
acceleration [L/T2], and time [T] must be related as
A. velocity = acceleration ´ time.
B. velocity = acceleration ´ time2.
C. velocity = acceleration2 ´ time2.
D. velocity = acceleration2 ´ time.
A. velocity = acceleration ´ time.
B. velocity = acceleration ´ time2.
C. velocity = acceleration2 ´ time2.
D. velocity = acceleration2 ´ time.
Section: 1.6 Dimensional Analysis
52. The equation for potential is U = mgh where U is
in kg·m2·s-2, m is in kg, and g is in m·s-2.
What are the units of h?
A. s2
B. s
C. kg
D. m
A. s2
B. s
C. kg
D. m
Section: 1.6 Dimensional Analysis
53. Assume everyone in the United States consumes one
soft drink in an aluminum can every two days. If there are 270 million
Americans, estimate how many tons of Aluminum needs to be recycled each year if
each can weighs 1/16 pound and one ton = 2000 pounds.
A. 750,000 tons
B. 1.5 million tons
C. 1.75 million tons
D. 3 million tons
E. 1,600,000 tons
A. 750,000 tons
B. 1.5 million tons
C. 1.75 million tons
D. 3 million tons
E. 1,600,000 tons
Section: 1.8 Approximation
54. Estimate how many textbooks of 1000 pages stacked
on top of each other it takes to make a stack of books 10 feet high.
A. 60
B. 50
C. 40
D. 30
E. 20
A. 60
B. 50
C. 40
D. 30
E. 20
Section: 1.8 Approximation
55. What is the order of magnitude of the number of
seconds in a year?
A. 4 ´ 10+7
B. 2 ´ 10+7
C. 3 ´ 10+7
D. 1 ´ 10+7
A. 4 ´ 10+7
B. 2 ´ 10+7
C. 3 ´ 10+7
D. 1 ´ 10+7
Section: 1.8 Approximation
56. A kilometer is approximately
A. ¼ mile.
B. 2 miles.
C. ½ mile.
D. 1 mile.
A. ¼ mile.
B. 2 miles.
C. ½ mile.
D. 1 mile.
Section: 1.8 Approximation
57. What is the order of magnitude of the number of
seconds in one year?
A. 3 ´ 107
B. 4 ´ 106
C. 3 ´ 106
D. 4 ´ 107
A. 3 ´ 107
B. 4 ´ 106
C. 3 ´ 106
D. 4 ´ 107
Section: 1.8 Approximation
58. Estimate the number of dollar bills (15.5 cm) put
end to end it would take to circle the Earth (radius = 6.40 ´ 103
km).
A. 9.5 ´ 10+8
B. 2.6 ´ 10+8
C. 3.7 ´ 10+7
D. 1.2 ´ 10+7
E. 8.5 ´ 10+6
A. 9.5 ´ 10+8
B. 2.6 ´ 10+8
C. 3.7 ´ 10+7
D. 1.2 ´ 10+7
E. 8.5 ´ 10+6
Section: 1.8 Approximation
59. Find the equation x = at + b
that fits the following data.
A. x = 45 t + 20
B. x = 35 t + 20
C. x = 35 t + 15
D. x = 25 t + 45
A. x = 45 t + 20
B. x = 35 t + 20
C. x = 35 t + 15
D. x = 25 t + 45
Section: 1.9 Graphs
60. Find the equation x = at2
+ b that fits the following data.
t(sec) 0 1 2 3 4 5
x(m) -16 -12 0 20 48 84
A. x = 4t2 + 16
B. x = 2t2 - 16
C. x = 4t2 - 16
D. x = 2t2 + 16
t(sec) 0 1 2 3 4 5
x(m) -16 -12 0 20 48 84
A. x = 4t2 + 16
B. x = 2t2 - 16
C. x = 4t2 - 16
D. x = 2t2 + 16
Section: 1.9 Graphs
61. Find the equation x = at2
+ b that fits the following data.
A. x = t2 + 18
B. x = 2t2 - 2
C. x = t2 + 3
D. x = 2t2 + 0
A. x = t2 + 18
B. x = 2t2 - 2
C. x = t2 + 3
D. x = 2t2 + 0
Section: 1.9 Graphs
62. Find the equation v2 = ah
+ b that fits the following data.
A. v2 = 4h + 0
B. v2 = 2h + 4
C. v2 = 4h + 4.90
D. v2 = 2h + 0
A. v2 = 4h + 0
B. v2 = 2h + 4
C. v2 = 4h + 4.90
D. v2 = 2h + 0
Section: 1.9 Graphs
63. Find the equation x = at + b
that fits the following data.
A. x = 20t - 80
B. x = -20t + 80
C. x = 40t + 80
D. x = -40t + 20
A. x = 20t - 80
B. x = -20t + 80
C. x = 40t + 80
D. x = -40t + 20
Section: 1.9 Graphs
64. Find the equation x = at2
+ b that fits the following data.
A. x = -4t2 + 60
B. x = 5t2 + 60
C. x = -2t2 + 60
D. x = 3t2 + 60
A. x = -4t2 + 60
B. x = 5t2 + 60
C. x = -2t2 + 60
D. x = 3t2 + 60
Section: 1.9 Graphs
65. Find the equation x = at2
+ bt that fits the following data.
A. x = 2t2 + 0
B. x = 6t2 - 3t
C. x = 2t2 + 2t
D. x = t2 + t
A. x = 2t2 + 0
B. x = 6t2 - 3t
C. x = 2t2 + 2t
D. x = t2 + t
Section: 1.9 Graphs
66. Find the equation v2 = ah
+ b that fits the following data.
A. v2 = 2h - 6
B. v2 = h - 4
C. v2 = 2h + 4
D. v2 = 2h - 4
A. v2 = 2h - 6
B. v2 = h - 4
C. v2 = 2h + 4
D. v2 = 2h - 4
Section: 1.9 Graphs
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